Asked by Lillianna

Tony had an equal number cranberry bars and walnut bars. He gave away 66 cranberry bars. He then had 4 times as many walnut bars as cranberry bars left. How many bars did he have at first?
Answered by DonHo



Let:
x= # of Cranberry Bars
y= # of Walnut Bars

x=4y-66

The problem states that there are equal # of cranberry bars to walnut bars. So, y=x

x=4x-66

Solve for x will give you 22 (which is the number of cranberry bars+walnut bars Tony had after he gave away 66)

So 22+66 = 88 bars

Solve for x
x= -22
Answered by Anonymous
This problem does not answer the actual question, "How many bars did he have at first?"
Answered by Anonymous
This solution does not answer the actual question, "How many bars did he have at first?" Shouldn't it also include the total of CB+WB?
Answered by PRIVATE
if it takes that much effort than ill get my but out of here. i got this question for 5th grade like why x and y and 4x and WHATEVER why does math have to be like this.
Answered by Anonymous
How did you get 22
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