Asked by Anonymous
Find a value for k so that the function is continuous.
f(x) = {(x^2 + 2x - 15)/(x - 3), x ≠ 3 and 2kx - 4, x = 3
Is k = 2?
f(x) = {(x^2 + 2x - 15)/(x - 3), x ≠ 3 and 2kx - 4, x = 3
Is k = 2?
Answers
Answered by
Steve
yes, k=2
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