Asked by gourav bhardwaj
Using Green's Theorem evaluate the integral ∮c(xydx + x^2y^2 dy) where C is the triangle with vertices (0 ,0), (1, 0) and (1, 2).
Answers
Answered by
Steve
well, you have
M = xy
N = x^2y^2
so the integral is just
∫∫<sub>R</sub> (N<sub>x</sub> - M<sub>y</sub>) dx dy
Along y=0, dy=0,
Along x=1, dx=0,
Along y=2x, dy = 2dx
Now just break the boundary into three parts, and evaluate each part. Watch the direction of the limits.
M = xy
N = x^2y^2
so the integral is just
∫∫<sub>R</sub> (N<sub>x</sub> - M<sub>y</sub>) dx dy
Along y=0, dy=0,
Along x=1, dx=0,
Along y=2x, dy = 2dx
Now just break the boundary into three parts, and evaluate each part. Watch the direction of the limits.
Answered by
Apsha
I need this answer
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