Question

In the figure a uniform, upward electric field of magnitude 1.90 × 103 N/C has been set up between two horizontal plates by charging the lower plate positively and the upper plate negatively. The plates have length L = 19.0 cm and separation d = 1.60 cm. An electron is then shot between the plates from the left edge of the lower plate. The initial velocity of the electron makes an angle θ = 48.0° with the lower plate and has a magnitude of 6.40 × 106 m/s. (a) Will the electron strike one of the plates? (b) If so, which plate, top or bottom? (c) How far horizontally from the left edge will the electron strike?

Answer 1

you know the horizontal and vertical components of velocity.
so you have to figure the time to reach the lower plate.
d=vivertical*time+1/2 Force*t^2/mass

force = Ee
d=initial distance to bottom plate.
figure time t. Now, figure the time to get through the maze (.19m/vhorizontal)
did the electron get through or not? If not, what was its horizontal postion at impact time to the lower plate?