Come on - this one is easy.
You have z+7+5 ends in 4
7+5=12, so z=2
Now work with that same idea to get x.
Remember that no one said that x,y,z had to be different from all the other digits already present.
7. Below, the standard addition algorithm is being used to add three two-digit numbers.
4z
27
+x5
y14
If x, y and z each represent a different digit from 0 to 9, what is the value of (x)(y)(z)?
1 answer
4 answers