Question

Let a, b, c and d all be real numbers and let x, y and z be variables. What is the solution (solve for x) to the equation a(x+y) + bz + c = d and state any restrictions (you cannot divide by zero).

I'm lost for this... Can someone help me?

Answer 1

just do what you always do. It does not matter whether the symbols are variables or constants.

a(x+y) + bz + c = d
ax + ay = d-bz-c
ax = d-ay-bz-c
x = (d-ay-bz-c)/a

Clearly, a cannot be zero. Otherwise, all's fair in love and algebra.