Asked by A GOODSTUDENT
Ben buys some oranges at the rate of 10 per $. He also buys equal number of oranges at the rate of 12 per $. He mixes them together and sells them at 15 per $. Find his loss or profit percent.
Answers
Answered by
Reiny
number bought at each price ---- x of them
so cost = x/10 + x/12 = 11x/60
selling price = 2x/15
difference = 2x/15 - 11x/60 = -x/20 , looks like a loss
percent loss = (x/20) / (11x/60)
= (1/20)(60/11) = .2727
or appr 27%
check:
suppose he bough 60 oranges at each price
at 10 oranges per $ , he paid $6.00
at 12 oranges per $, he paid $5.00
so he paid $11 for 120 oranges
selling them at 15 per $, he got back $120/15
or $8.00
so his loss was $3.00
percent loss = 3/11 = .2727..
so cost = x/10 + x/12 = 11x/60
selling price = 2x/15
difference = 2x/15 - 11x/60 = -x/20 , looks like a loss
percent loss = (x/20) / (11x/60)
= (1/20)(60/11) = .2727
or appr 27%
check:
suppose he bough 60 oranges at each price
at 10 oranges per $ , he paid $6.00
at 12 oranges per $, he paid $5.00
so he paid $11 for 120 oranges
selling them at 15 per $, he got back $120/15
or $8.00
so his loss was $3.00
percent loss = 3/11 = .2727..
Answered by
A GOODSTUDENT
Ahh !😊
Now I get it.
Thanks
Now I get it.
Thanks
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