Asked by Asha
The ration of prices of two horses was 16:23.Two years later when the price of the first has risen by 10% and that of the second by rs.477, the ratio of their prices becomes 11:20. Find the original prices of the two horses.
Answers
Answered by
Reiny
Let their respective prices be 16x and 23x
new price of first horse = 1.1(16x) = 17.6x
new price of second horse = 23x + 477
17.6x/(23x+477) = 11/20
352x = 253x + 5247
99x = 5247
x = 53
the first horse cost 16(53) or 848
the 2nd horse cost 23(53) or 1219
check:
848 : 1219 = 16 : 23
I will leave the check of the 2nd condition up to you.
new price of first horse = 1.1(16x) = 17.6x
new price of second horse = 23x + 477
17.6x/(23x+477) = 11/20
352x = 253x + 5247
99x = 5247
x = 53
the first horse cost 16(53) or 848
the 2nd horse cost 23(53) or 1219
check:
848 : 1219 = 16 : 23
I will leave the check of the 2nd condition up to you.
Answered by
Asha
Its right....thank u sir
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