Asked by Asha

Evaluate:
Log243/120-log54/75+log24/27-log5/2
Answered by Anonymous
what is

log (243*24*75*2/120*54*27*5)=
log (1)=
0
Answered by Steve
or, it is

5log3 - (3log2 + log3 + log5) - (log2 + 3log3) + (log3 + 2log5) + (3log2 + log3) - 3log3 - log5 + log2 = 0
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