The toxic metal cadmium Cd2+ has a tendency to complex with as many as 4 Cl- ions. The complexation reactions can be written as:
Cd2+ + Cl- ---> CdCl+ ``````` log Kf,1 = 1.98
Cd2+ + 2Cl- ---> CdCl20 `````` log Kf,2 =2.60
Cd2+ + 3Cl- ---> CdCl3- `````` log Kf,3 = 2.40
Cd2+ + 4Cl- ----> CdCl42- ````` log Kf,4 = 2.50
What is the percentage of total Cd2+ in a solution that remains uncomplexed (free Cd2+ ) if the Cl- concentration is 0.005 M (ignore activity coefficient correction, assume activities equal concentrations).