Asked by erika
At a high temperature, the equilibrium constant for the decomposition of hydrogen iodide is 65.0. If the initial concentration of HI is 1.60 M, what is the concentration of hydrogen at equilibrium?
2Hl(g) H2(g) + I2(g)
A. 1.42 M
B. 0.753 M
C. 0.240 M
D. 0.802 M
I'm actually not sure how to work through this question at all so I don't have any ideas as to which answer it is. Can someone show me how to work through it?
2Hl(g) H2(g) + I2(g)
A. 1.42 M
B. 0.753 M
C. 0.240 M
D. 0.802 M
I'm actually not sure how to work through this question at all so I don't have any ideas as to which answer it is. Can someone show me how to work through it?
Answers
Answered by
DrBob222
......2HI ==> H2 + I2
I.....1.60.....0....0
C.....-2x......x....x
E....1.60-2x...x....x
Substitutethe E line into the Keq expression and solve for x.
I.....1.60.....0....0
C.....-2x......x....x
E....1.60-2x...x....x
Substitutethe E line into the Keq expression and solve for x.
Answered by
drbob hater
Dr. Bob, your responses are not good whatsoever.
Answered by
Kendall
0.753
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