Asked by PLEASE HELP (MATH)
Sam's age is five years more than twice Jessica's age. Together, the sum of their ages is 17.
Answers
Answered by
bobpursley
I just did this for 8thgradestudent.
Answered by
Graham
I already answered this in the previous question, but here it is again:
"Sam's age is five years more than twice Jessica's age."
So, Sam's age, which I will designate a "s" is 5 years more than twice Jessica's age, which I will designate as "j".
From this we can realize that twice Jessica's age (2j) plus 5 is equal to Sam's age. From this, we can get the equation:
s = 2j + 5
"Together, the sum of their ages is 17."
This one's pretty straightforward:
s + j = 17
So now we have the system of equations:
s = 2j + 5
s + j = 17
Since we know that s = 2j + 5, we can substitute 2j + 5 for s in the second equation:
s + j = 17
(2j + 5) + j = 17
By using algebra to solve for J in the equation above, you will arrive at the correct answer.
"Sam's age is five years more than twice Jessica's age."
So, Sam's age, which I will designate a "s" is 5 years more than twice Jessica's age, which I will designate as "j".
From this we can realize that twice Jessica's age (2j) plus 5 is equal to Sam's age. From this, we can get the equation:
s = 2j + 5
"Together, the sum of their ages is 17."
This one's pretty straightforward:
s + j = 17
So now we have the system of equations:
s = 2j + 5
s + j = 17
Since we know that s = 2j + 5, we can substitute 2j + 5 for s in the second equation:
s + j = 17
(2j + 5) + j = 17
By using algebra to solve for J in the equation above, you will arrive at the correct answer.
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