Asked by Mandy
                The highest wall that a projectile can clear is 17m, when the projectile is launched at an angle of 35.0 degrees above the horizontal. What is the projectile's launch speed?
            
            
        Answers
                    Answered by
            bobpursley
            
    at the top, 
mgh=1/2 m v'^2 where v' is the initlal vertical velocity. find v' then
so vlaunch=v'/sin35
    
mgh=1/2 m v'^2 where v' is the initlal vertical velocity. find v' then
so vlaunch=v'/sin35
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