Question
The highest wall that a projectile can clear is 17m, when the projectile is launched at an angle of 35.0 degrees above the horizontal. What is the projectile's launch speed?
Answers
bobpursley
at the top,
mgh=1/2 m v'^2 where v' is the initlal vertical velocity. find v' then
so vlaunch=v'/sin35
mgh=1/2 m v'^2 where v' is the initlal vertical velocity. find v' then
so vlaunch=v'/sin35