Asked by Mandy

The highest wall that a projectile can clear is 17m, when the projectile is launched at an angle of 35.0 degrees above the horizontal. What is the projectile's launch speed?

Answers

Answered by bobpursley
at the top,
mgh=1/2 m v'^2 where v' is the initlal vertical velocity. find v' then

so vlaunch=v'/sin35
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