Asked by oding
a liquid cools in 6 minutes from 80degrees Celsius to 60degrees Celsius .what will it's temperature be after 10 minutes.temperature of the surrounding is 30degrees Celsius
Answers
Answered by
Steve
Are you using Newton's cooling law?
T(t) = 30 + 50e^(-kt)
Now use the fact that
T(6)=60 to find k.
Then evaluate T(10)
T(t) = 30 + 50e^(-kt)
Now use the fact that
T(6)=60 to find k.
Then evaluate T(10)
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