Question

a slow growing population of animals increases with time (years). the size of the population is given by P(t)=100+0.6t^2-0.004t^3. how fast is the population changing after 10 years?

Answer 1

clue: "how fast is ... changing" means you want the derivative.
dP/dt = 1.2t - 0.012t^2
So, plug in t=10

Answer 2

If you haven't yet covered derivatives, you must have studied an approximation method, such as

[f(10+h)-f(10)]/h

for small values of h.

Answer 3

can someone please help