Asked by Faye
a slow growing population of animals increases with time (years). the size of the population is given by P(t)=100+0.6t^2-0.004t^3. how fast is the population changing after 10 years?
Answers
Answered by
Steve
clue: "how fast is ... changing" means you want the derivative.
dP/dt = 1.2t - 0.012t^2
So, plug in t=10
dP/dt = 1.2t - 0.012t^2
So, plug in t=10
Answered by
Steve
If you haven't yet covered derivatives, you must have studied an approximation method, such as
[f(10+h)-f(10)]/h
for small values of h.
[f(10+h)-f(10)]/h
for small values of h.
Answered by
Ange
can someone please help
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