Asked by Anonymous
Find the area of a regular hexagon with the given measurement.
4-inch side
A = sq. in.
4-inch side
A = sq. in.
Answers
Answered by
Bosnian
Area of a regular hexagon =
[ 3 sqroot ( 3 ) / 2 ] * a ^ 2
Where, a is the side of the hexagon.
A = [ 3 sqroot ( 3 ) / 2 ] * a ^ 2
A = [ 3 sqroot ( 3 ) / 2 ] * 4 ^ 2
A = [ 3 sqroot ( 3 ) / 2 ] * 16
A = [ 3 sqroot ( 3 ) / 2 ] * 2 * 8
A = 3 sqroot ( 3 ) * 8
A = 24 sqroot ( 3 ) in ^ 2
A = 41.56922 in ^ 2
[ 3 sqroot ( 3 ) / 2 ] * a ^ 2
Where, a is the side of the hexagon.
A = [ 3 sqroot ( 3 ) / 2 ] * a ^ 2
A = [ 3 sqroot ( 3 ) / 2 ] * 4 ^ 2
A = [ 3 sqroot ( 3 ) / 2 ] * 16
A = [ 3 sqroot ( 3 ) / 2 ] * 2 * 8
A = 3 sqroot ( 3 ) * 8
A = 24 sqroot ( 3 ) in ^ 2
A = 41.56922 in ^ 2
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