Asked by margie
Problem:
(y+2)/(y) = 1/(y-5)
Directions:
Solve the rational expression.
Remember that if:
a/b = c/d
then:
a * d = b * c
I believe in school they call this the fraction crossover rule or fraction cross rule or something like that.
i would work it like a proportion and cross multiply and then divide.
(y+2)/(y) = 1/(y-5)
(y-5)(y+2) = y
y^2-3y-10 = y
y^2-4y-10 = 0
Since there are no factors of 10 whose difference is 4, use the quadratic formula to solve.
(y+2)/(y) = 1/(y-5)
Directions:
Solve the rational expression.
Remember that if:
a/b = c/d
then:
a * d = b * c
I believe in school they call this the fraction crossover rule or fraction cross rule or something like that.
i would work it like a proportion and cross multiply and then divide.
(y+2)/(y) = 1/(y-5)
(y-5)(y+2) = y
y^2-3y-10 = y
y^2-4y-10 = 0
Since there are no factors of 10 whose difference is 4, use the quadratic formula to solve.
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