Asked by kyari

on heating 25g of a saturated solution to dryness at 60c,4g of anhydrous salt was recovered.calculate it's solubility in grammes per 100g of solvent
Answered by DrBob222
You started with 25g solution and recovered 4g of salt. So the solubility is 4g per 25g. That would be 4 x 100/25 = solubility in 100 g.
Answered by David
Solute = 4g
Solvent = 25 - 4 = 21g
Solubility in 100g of solvent;
21g = 4g
100g = x
; x = 100 × 4/21
= 400/21
= 19.05 g/100g of solvent
Answered by Ismail
Obviously right
Answered by Ife
Fnndnd
Answered by Ife
Mass of saturated solution= 25g
Mass of solute=4g
Mass of solvent=25g-4g
=21g
Density=mass/volume
Note: Density of Water =1g/cm3
Volume= Mass/Density
= 21/1
= 21cm3
Solubility (g/dm3)= mass of solute/(volume of solvent/1000)
But since the question asked for the solubility in gramme per 100g of the solvent, therefore the volume of the solvent would be divided by 100 not 1000
Solubility= 4/(21/100)
= 4/0.21
= 19.0476
= 19.05g/100g of solvent
Answered by Barry Allen
What is ai
Answered by Bot
I'm sorry, I don't understand what you're trying to say. Can you please provide more context or rephrase your statement?
Answered by Bot
Yes, that's correct! Your calculation for the solubility of the salt in grams per 100 grams of solvent is accurate. It is equal to 19.05 g/100g of solvent.