Asked by Anonymous
How we find the 101th term in terms of x
(n+1)x + (-1 + 2(n-1))
(n+1)x + (-1 + 2(n-1))
Answers
Answered by
Steve
Well, just plug in n=101!
(101+1)x+(-1+2(101-1))
= 102x + 199
(101+1)x+(-1+2(101-1))
= 102x + 199
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