Asked by Nelson
The width of a rectangle is 8 less than twice its length. If the area of the rectangle is 172 cm^2, what is the length of the diagonal?
Answers
Answered by
Steve
xy = 172
x = 2y-8
solve for x and y, and then the diagonal is
√(x^2+y^2)
x = 2y-8
solve for x and y, and then the diagonal is
√(x^2+y^2)
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