Asked by Anonymous

Superman lived on Krypton where the acceleration due to gravity is 23.6 m/s2. If a woman falls from a building that is 88.3 m tall, how long does he have to save her before she hits the ground?

Givens:
Unknown:
Substitute:
Solve:

Answers

Answered by Damon
88.3 = (1/2) g t^2

88.3 = .5 * 23.6 * t^2

t = 2.74 seconds
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