Asked by Kitty
Simplify
1) 4r+3-9r^2+7r
2) (4h^3+3h+1)-(-5h^3+6h-2)
3) 5k (3-4k)
4) (2x-3)(4x+3)
5) (4x-3)(4x+3)
My answers:
1) 11r+3-9r^2
2) this one I am confused about
3) confused
4) 7x×7
5) 8x-6
Please help me
1) 4r+3-9r^2+7r
2) (4h^3+3h+1)-(-5h^3+6h-2)
3) 5k (3-4k)
4) (2x-3)(4x+3)
5) (4x-3)(4x+3)
My answers:
1) 11r+3-9r^2
2) this one I am confused about
3) confused
4) 7x×7
5) 8x-6
Please help me
Answers
Answered by
Reiny
#2:
(4h^3+3h+1)-(-5h^3+6h-2)
think of it as
(4h^3+3h+1)-1(-5h^3+6h-2)
= 4h^3 + 3h + 1 + 5h^2 - 6h + 2
= 9h^2 -3h + 3
#3
5k (3-4k)
= 15k - 20k^2 by the distributive property
(4h^3+3h+1)-(-5h^3+6h-2)
think of it as
(4h^3+3h+1)-1(-5h^3+6h-2)
= 4h^3 + 3h + 1 + 5h^2 - 6h + 2
= 9h^2 -3h + 3
#3
5k (3-4k)
= 15k - 20k^2 by the distributive property
Answered by
Reiny
#4, oh dear!!!
(2x-3)(4x+3)
= 8x^2 + 6x - 12x - 9
= 8x^2 - 6x - 9
#5 , same as #4
(4x-3)(4x+3)
= 16x^2 + 12x - 12x - 9
= 16x^2 - 9 <--- called the difference of squares
make sure you are familiar with FOIL,
F : multiply the firsts
O : multiply the "outers"
I : multiply the "inners"
L: multiply the "lasts"
(2x-3)(4x+3)
= 8x^2 + 6x - 12x - 9
= 8x^2 - 6x - 9
#5 , same as #4
(4x-3)(4x+3)
= 16x^2 + 12x - 12x - 9
= 16x^2 - 9 <--- called the difference of squares
make sure you are familiar with FOIL,
F : multiply the firsts
O : multiply the "outers"
I : multiply the "inners"
L: multiply the "lasts"
Answered by
Lol
Uh ye
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