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A baseball catcher puts on an exhibition by catching a .150-kg ball dropped from a helicopter at a height of 100m above the catcher. If the catcher "gives" with the ball for a distance of .750m while catching it, what avg. force is exerted on the mitt by the ball? (g = 9.8 m/s^2)

is this correct?
KE = mgh
KE = (.150)(9.8)(100) = 147 J
16 years ago

Answers

habib
yes
13 years ago

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