Asked by Shonda
Graph the following equation and state the axes of symmetry 3x^2-3y=12x+9
Answers
Answered by
Reiny
3x^2-3y=12x+9
divide by 3 and re-arrange
y = x^2 - 4x - 3
complete the square ...
y = x^2 - 4x + 4 - 4 - 3
= (x - 2)^2 - 7
http://www.wolframalpha.com/input/?i=plot+y+%3D+(x+-+2)%5E2+-+7
axis of symmetry: x = 2
divide by 3 and re-arrange
y = x^2 - 4x - 3
complete the square ...
y = x^2 - 4x + 4 - 4 - 3
= (x - 2)^2 - 7
http://www.wolframalpha.com/input/?i=plot+y+%3D+(x+-+2)%5E2+-+7
axis of symmetry: x = 2
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