Question

An arrow is shot vertically upwards with an initial velocity of 14 m/s . Calculate the height reached

Answer 1

potential energy at top = kinetic energy at bottom

m g h = (1/2) m v^2

h = v^2/(2g)

Answer 2

max height is reached when it comes to a stop

v = 14-gt
solve for t when v=0 and use that to find h in

h = 14t - g/2 t^2

Or, use (or derive) a simpler more direct formula without finding t first.