Asked by CC
How can I solve this problem?
A circle has diameter [AB]. The centre of the circle is (1,3), and B has coordinates (4,-1).
# Find the coordinates of A.
# Find the length of the diameter.
HELP ME PLEASE
A circle has diameter [AB]. The centre of the circle is (1,3), and B has coordinates (4,-1).
# Find the coordinates of A.
# Find the length of the diameter.
HELP ME PLEASE
Answers
Answered by
bobpursley
diameter= 2*(sqrt((4+1)^2 + (-1+3)^2)
diameter=2 sqrt(25+4)=2sqrt29
Now, A must be on the other side of B, or A is (-2,7)
diameter=2 sqrt(25+4)=2sqrt29
Now, A must be on the other side of B, or A is (-2,7)
Answered by
CC
Why √29 to (-2,7)?
How can I know?
Answered by
Steve
A is the same distance from (1,3) as B is.
You don't need to know that the distance is √29. You just need to subtract the same values from (1,3) as were added to get to (4,-1)
(1,3)<b>+</b>(3,-4) = (4,-1)
So, you need
(1,3)<b>-</b>(3,-4) = (-2,7)
You don't need to know that the distance is √29. You just need to subtract the same values from (1,3) as were added to get to (4,-1)
(1,3)<b>+</b>(3,-4) = (4,-1)
So, you need
(1,3)<b>-</b>(3,-4) = (-2,7)
Answered by
CC
OK, I understand.
Thank you very much!!
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