Question

At 603 K, Kc for the reaction NH4Cl <===> NH3 + HCl is 0.011. What is the equilibrium concentration of NH3 if the initial concentration of NH4Cl is 0.500 M. Please help me with this question because i got 2 answers so prove me.

Answer 1

206

Answer 2

Why not show your work for the two answers you have so we can find the error. That's a lot easier than us working the problem and letting you look for the error.

......NH4Cl(g) --> NH3(g) + HCl(g)
I......0.5..........0........0
C......-x...........x........x
E.....0.5-x.........x........x

Kc = 0.011 = (x)(x)/(0.50x)
Solve for x.

Answer 3

Please answer me with the working out...

Answer 4

please can you help me with the correct answer