Question

From the data below, calculate the total heat (in J) needed to convert 22.00 g of icea t -6.00 C to liquid water at 0.500 C.

melting point at 1 atm: 0.0 C
Hfusion: 6.02 KJ/mol
cliquid: 4.21 J/g C
csolid: 2.09 J / g C

My answer is about 300 J short of the correct answer. It says it's 7670 J as the correct answer, but I keep getting 7,362 J. Not sure what I'm doing wrong.

My equations are as followed:
q= (1.22g)(2.09J/g C)(6.00C) = 15.29 (csolid, using Q=MC/\T equation)
q= (1.22g)(6.02KJ/mol)=7.3444 KJ (multiply this by 1,000 to make it into Joules = 7344)
(q=mHFusion equation)
q= (1.22g)(4.21J/g C)(.5)= 2.56 J
(q=MC/\T equation, cliquid)
Add all these up and I get 7,362 J.

Answer 1

realized my mistake