Asked by Jennifer
A hot dog cart at the entrance of the Stadium sells hot dogs ($3.50) and hamburger ($5.25) for a total of $1,225.00. If it sells twice as many hot dogs as hamburgers, how many of each did it sell?
Answers
Answered by
Jennifer
3.50x + 5.25y =2(3.50x)
3.50x + 5.25y = 1,225.00
Use Elimination Method
-3.50( 3.50x + 5.25y ) = -3.50(7)
-12.25x - 18.375y = -24.5
3.50 + 5.25y = 1,225.00
3.50x + 5.25y = 1,225.00
Use Elimination Method
-3.50( 3.50x + 5.25y ) = -3.50(7)
-12.25x - 18.375y = -24.5
3.50 + 5.25y = 1,225.00
Answered by
Steve
Hmm. I get
x = 2y
3.50x + 5.25y = 1,225.00
Having twice as many dogs as burgers has nothing to do with their prices.
x = 2y
3.50x + 5.25y = 1,225.00
Having twice as many dogs as burgers has nothing to do with their prices.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.