Question
A hot dog cart at the entrance of the Stadium sells hot dogs ($3.50) and hamburger ($5.25) for a total of $1,225.00. If it sells twice as many hot dogs as hamburgers, how many of each did it sell?
Answers
Jennifer
3.50x + 5.25y =2(3.50x)
3.50x + 5.25y = 1,225.00
Use Elimination Method
-3.50( 3.50x + 5.25y ) = -3.50(7)
-12.25x - 18.375y = -24.5
3.50 + 5.25y = 1,225.00
3.50x + 5.25y = 1,225.00
Use Elimination Method
-3.50( 3.50x + 5.25y ) = -3.50(7)
-12.25x - 18.375y = -24.5
3.50 + 5.25y = 1,225.00
Steve
Hmm. I get
x = 2y
3.50x + 5.25y = 1,225.00
Having twice as many dogs as burgers has nothing to do with their prices.
x = 2y
3.50x + 5.25y = 1,225.00
Having twice as many dogs as burgers has nothing to do with their prices.