Asked by Willow
Evaluate the function.
h(a) = 2^a+1; Find h(a - 4)
h(a) = 2^a+1; Find h(a - 4)
Answers
Answered by
Steve
just make the substitution:
h(a-4) = 2^(a-4)+1 = 2^a/16 + 1
or, if you were careless with parentheses,
h(a-4) = 2^(a-4+1) = 2^(a-3) = 2^a/8
h(a-4) = 2^(a-4)+1 = 2^a/16 + 1
or, if you were careless with parentheses,
h(a-4) = 2^(a-4+1) = 2^(a-3) = 2^a/8
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