A soccer ball is released from the top of a smooth incline. After 4.54 s the ball travels 8.1 m. One second later it has reached the bottom of the incline.

Question

Assume the ball's acceleration is constant and determine its value ( m/s2).

How long is the incline?

Answer 1

s = 1/2 at^2, so
1/2 a * 4.54^2 = 8.1

Now use that to figure how far it goes in the next second.
v = a*t
s = v*1 + 1/2 a * 1^2