Question

Find the equation of the tangent to the graph of f(x)=2x^4 (to the power of 4) that has slope 1.

Derivative is 8 x^3. This equals 1 at
x = 1/2. At this point the y-coordinate is f(1/2) = 1/8. The equation of the tangent line is thus:

1/8 + 1*(x-1/2) =

x - 3/8

Thank you for your assistance.

It clarified my thinking in regards to similar questions.

Related Questions

find the equation of a quadratic function whose graph is tangent at x=1 to the line whose slope8, ta... Consider the function f(x)= -cos3x -4sin3x. (a)Find the equation of the line normal to the graph of... Let f(x) be a cubic polynomial function such that y=13(x-1)+4 is tangent to the graph of f(x)at (1,... 1. use the definition mtan=(f(x)-f(x))/(x-a) to find the SLOPE of the line tangent to the graph of f...