At normal temperature and pressure, air has a density of 0.001184 g/mL. What is the mass of air in a room that is 3.93 m by 2.28 m by 2.25 m?

Convert the room measurements to cm, then volume comes out in cm^3 (or mL).

mass = volume in cc(mL) x density (in g/mL) = ? grams

23,870.5056

23,870.5056g

To calculate the mass of air in the room, we first need to calculate the volume of the room.

The volume of a rectangular room can be calculated by multiplying its length, width, and height:

Volume = Length × Width × Height

In this case, the length is 3.93 m, the width is 2.28 m, and the height is 2.25 m. Plugging these values into the equation, we get:

Volume = 3.93 m × 2.28 m × 2.25 m = 20.5881 m³

The density of air is given as 0.001184 g/mL, which is equivalent to 0.001184 g/cm³. However, the volume of the room is given in cubic meters, so we need to convert the density to match the units. Since 1 m³ is equal to 1,000,000 cm³, we can convert the density of air to grams per cubic meter (g/m³) by multiplying it by 1,000,000:

Density of air = 0.001184 g/cm³ × 1,000,000 = 1184 g/m³

Now that we have the volume of the room and the density of air, we can finally calculate the mass of air in the room:

Mass of air = Volume × Density of air

Mass of air = 20.5881 m³ × 1184 g/m³ = 24,353.4804 g

Therefore, the mass of air in the room is approximately 24,353.4804 grams.