Asked by A GOODSTUDENT
The tip of a plant was 6cm above a lake but a sudden wind forced the plant to move 10 cm fat from its original position and then it submerged into the lake. Find the depth of the lake upto which it was sinking.
Please help!!!!!!!!!!
Please help!!!!!!!!!!
Answers
Answered by
Reiny
Make a sketch.
Think of the plant as a radius of a circle the plant would draw out.
Draw in a horizontal to show the lake.
At the vertical let OP be the length of the plant,
O is the centre and P at the top.
then draw a horizontal 6 cm below P so the plant touches at A and B.
OP = x , AP = 6 , AB = 10, and OB = x
then OA = x-6
by Pythagoras,
x^2 = 10^2 + (x-6)^2
x^2 = 100 + x^2 - 12x + 36
12x = 136
x = 136/12 = 34/3 or 11 1/3
then the depth of the plant below water
= 34/3 - 6
= 16/3 or
5 1/3 cm
Think of the plant as a radius of a circle the plant would draw out.
Draw in a horizontal to show the lake.
At the vertical let OP be the length of the plant,
O is the centre and P at the top.
then draw a horizontal 6 cm below P so the plant touches at A and B.
OP = x , AP = 6 , AB = 10, and OB = x
then OA = x-6
by Pythagoras,
x^2 = 10^2 + (x-6)^2
x^2 = 100 + x^2 - 12x + 36
12x = 136
x = 136/12 = 34/3 or 11 1/3
then the depth of the plant below water
= 34/3 - 6
= 16/3 or
5 1/3 cm
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.