Question

Solve the system by Gauss - Jordan elimination.
{ 1/3 x + 3/4 y - 2/3 z = -8 x + 1/2 y + 1/3 z = 18 1/6 x = 1/8 y - z = -24


a. (−6, 8, −24)
b. (−6, −8, −24)
c. (0, 8, −24)
d. (6,8,24)
e. (6, −8, 24)

Answer 1

Argghhh, hard to read, besides, you appear to have a typo near the end
1/6 x = 1/8 y - z = -24 -----> 1/6 x + 1/8 y - z = -24


did you mean:
1/3 x + 3/4 y - 2/3 z = -8
x + 1/2 y + 1/3 z = 18
1/6 x + 1/8 y - z = -24 ??

if so , I would clean them up first,
1/3 x + 3/4 y - 2/3 z = -8
times 12
4x + 9y - 6z = 96

x + 1/2 y + 1/3 z = 18
times 6
6x + 3y + 2z = 108

etc.

could you do it now?

btw, Wolfram says this:
http://www.wolframalpha.com/input/?i=solve+1%2F3+x+%2B+3%2F4+y+-+2%2F3+z+%3D+-8,+x+%2B+1%2F2+y+%2B+1%2F3+z+%3D+18,+1%2F6+x+%2B+1%2F8+y+-+z+%3D+-24