Asked by Unknown
A car, in overtaking trailer, uniformly accelerated its speed from 40 kph to 90 kph in 8 seconds. Calculate the distance traveled during the period of acceleration.
Answers
Answered by
Steve
a = 50kph/8s = 25/4 km/hr/s = 1.736 m/s^2
Vo = 40 km/hr = 11.11 m/s, so
s = Vo*t + a/2 t^2
now just plug in the values for Vo,a,t
Vo = 40 km/hr = 11.11 m/s, so
s = Vo*t + a/2 t^2
now just plug in the values for Vo,a,t
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