Asked by Unknown
                A car, in overtaking trailer, uniformly accelerated its speed from 40 kph to 90 kph in 8 seconds. Calculate the distance traveled during the period of acceleration.
            
            
        Answers
                    Answered by
            Steve
            
    a = 50kph/8s = 25/4 km/hr/s = 1.736 m/s^2
Vo = 40 km/hr = 11.11 m/s, so
s = Vo*t + a/2 t^2
now just plug in the values for Vo,a,t
    
Vo = 40 km/hr = 11.11 m/s, so
s = Vo*t + a/2 t^2
now just plug in the values for Vo,a,t
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.