Asked by Anonymous
The length of a rectangle is twice its width. The perimeter of the rectangle is 126ft.
Answers
Answered by
A GOODSTUDENT
Length = 2* width
Let length be l and w be the width
Then
2(l+w)=126
2(3w)=126
W=126/6
Find out what you want to find.
And please type the full question. That one seems to be just a statement.
Let length be l and w be the width
Then
2(l+w)=126
2(3w)=126
W=126/6
Find out what you want to find.
And please type the full question. That one seems to be just a statement.
Answered by
Bosnian
l = length
w = width
P = perimeter
l = 2 w
P = 2 ( l + w ) = 126
2 ( 2 w + w ) = 126
2 * 3 w = 126
6 w = 126
w = 126 / 6 = 21 ft
l = 2 w = 2 * 21 = 42 ft
w = width
P = perimeter
l = 2 w
P = 2 ( l + w ) = 126
2 ( 2 w + w ) = 126
2 * 3 w = 126
6 w = 126
w = 126 / 6 = 21 ft
l = 2 w = 2 * 21 = 42 ft
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