Asked by SARAH
JOHN WANTS TO PADDLE HIS CANOE ACROSS A RIVER THAT IS 200M WIDE, HE STARTS FROM THE EAST SIDE. THE WATER CURRENT FLOWS NORTH-SOUTH AT 0.5MS^-1. IT TAKES JOHN 252S TO CROSS THE RIVER.
1. DRAW A DIAGRAM TO GRAPHICALLY REPRESENT THE VELOCTY VECTORS OF THE WATER CANOE AND THEIR RESULTANT
2.CALCULATE THE DIRECTION JOHN HEADED HIS CNOE TO FOLLOW A COURSE DUE WEST ACROSS THE RIVER
1. DRAW A DIAGRAM TO GRAPHICALLY REPRESENT THE VELOCTY VECTORS OF THE WATER CANOE AND THEIR RESULTANT
2.CALCULATE THE DIRECTION JOHN HEADED HIS CNOE TO FOLLOW A COURSE DUE WEST ACROSS THE RIVER
Answers
Answered by
Damon
He ends up going 200 meters west in 252 seconds.
Therefore we an figure out his west velocity component:
Vw = 200/252 m/s
Meanwhile he is carried south at .5 m/s so he will have to have a north component of
Vn = .5 m/s
So we can figure the angle north of west he has to head.
tan A = Vn/Vw
Head A degrees north of west and you go straight west :)
Therefore we an figure out his west velocity component:
Vw = 200/252 m/s
Meanwhile he is carried south at .5 m/s so he will have to have a north component of
Vn = .5 m/s
So we can figure the angle north of west he has to head.
tan A = Vn/Vw
Head A degrees north of west and you go straight west :)
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