II Newton's law:
a=F/m
a=16N/4kg
a=4m/s^2
a=Δv/Δt
Δv=a x Δt
Δv=4m/s^2 x 2s
Δv=8m/s
change in velocity is 8m/s
a=F/m
a=16N/4kg
a=4m/s^2
a=Δv/Δt
Δv=a x Δt
Δv=4m/s^2 x 2s
Δv=8m/s
change in velocity is 8m/s
Using Newton's second law, F = ma, where F is the force, m is the mass, and a is the acceleration, we can rearrange the equation to find the acceleration. So, a = F/m.
Plugging in the values, we get a = 16N / 4kg, which gives us an acceleration of 4 m/s².
Now, since the initial velocity wasn't provided, let's assume it was zero.
Using a standard kinematic equation, vf = vi + at, we can find the final velocity (vf). Plugging in the values, we get vf = 0 + 4 m/s² * 2 sec, which equals 8 m/s.
So, the change in velocity would be 8 m/s, assuming no other forces are acting on the body. Keep in mind, though, this is all hypothetical, and in reality, various other factors would affect the final result.
Given:
Mass (m) = 4 kg
Force (F) = 16 N
Time (t) = 2 sec
To find the acceleration (a), rearrange the formula as follows:
F = ma
a = F/m
Substitute the values:
a = 16 N / 4 kg
a = 4 m/s²
Now, we can use the formula for average acceleration:
a = (change in velocity) / (change in time)
Rearrange the formula to solve for the change in velocity:
change in velocity = a × change in time
Substitute the values:
change in velocity = 4 m/s² × 2 sec
change in velocity = 8 m/s
Therefore, the change in velocity produced on the body of mass 4 kg, if a contact force of 16 N acts on it for 2 seconds, is 8 m/s.
Force = Mass × Acceleration
Rearranging the equation, we can solve for the acceleration:
Acceleration = Force / Mass
In this case, the force acting on the body is given as 16 N, and the mass of the body is 4 kg.
Acceleration = 16 N / 4 kg = 4 m/s^2
Now, we can use the equation of motion to find the change in velocity:
Change in Velocity = Acceleration × Time
Given that the time is 2 seconds, we can calculate the change in velocity:
Change in Velocity = 4 m/s^2 × 2 s = 8 m/s
Therefore, the body would experience a change in velocity of 8 m/s when a contact force of 16 N acts on it for 2 seconds.