Asked by sanusi
what change in velocity would be produced on a body of mass 4kg, if a contact force of 16N act on it for 2sec.
Answers
Answered by
Pevojed
II Newton's law:
a=F/m
a=16N/4kg
a=4m/s^2
a=Δv/Δt
Δv=a x Δt
Δv=4m/s^2 x 2s
Δv=8m/s
change in velocity is 8m/s
a=F/m
a=16N/4kg
a=4m/s^2
a=Δv/Δt
Δv=a x Δt
Δv=4m/s^2 x 2s
Δv=8m/s
change in velocity is 8m/s
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