Asked by MIKE HUNT


An 70 kg man drops from rest on a diving
board 3.2 m above the surface of the water
and comes to rest 0.57 s after reaching the
water.

The acceleration due to gravity is
9.81 m/s2.

What force does the water exert on the
man? Answer in units of N.
Answered by bobpursley
avgforce*time=change in momentum
Calculate the velocity at impact (free fall, 3.2m), multiply by mass.
Answered by POOPY MCPOOPPANTS
SHOUT OUT TO MR LONGS CLASS!!!!!!!!!!!!!!!!!!!!
Answered by jack
12
Answered by Anonymous
910
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