Question

An 70 kg man drops from rest on a diving
board 3.2 m above the surface of the water
and comes to rest 0.57 s after reaching the
water.

The acceleration due to gravity is
9.81 m/s2.

What force does the water exert on the
man? Answer in units of N.

Answer 1

avgforce*time=change in momentum
Calculate the velocity at impact (free fall, 3.2m), multiply by mass.

Answer 2

SHOUT OUT TO MR LONGS CLASS!!!!!!!!!!!!!!!!!!!!

Answer 3

12

Answer 4

910