Now we substitute y in the first equation:
3x + 2((4/3)x - 16/3) = -5
3x + (8/3)x - 32/3 = -5
Now, we find a common denominator to combine the fractions:
(9/3)x + (8/3)x = (-5 + 32/3)
(17/3)x = 7/3
Now, we can find the value of x by dividing both sides by 17/3
(17/3)x / (17/3) = 7/3 / (17/3)
x = 7/17
Now, substitute x back into the equation we found for y:
y = (4/3)(7/17) - 16/3
y = 28/51 - 16/3
y = 28/51 - 272/51
y = -244/51
So the solution of the linear system is x = 7/17 and y = -244/51.
use substitution to solve the linear system
3x+2y=-5
4x-3y=16
help plz!!!
Solve for y in one formula, and then substitute that value for y in the other formula to solve for x. Once you find x, substitute that value into either formula to get the value for y.
-3y = 16 - 4x
y = (16 - 4x)/-3 = (4/3)x - 16/3
I'll let you do the rest.
I hope this helps. Thanks for asking.
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1 answer