Asked by Anonymous
What would the domain of
Y=_/2x+14)/(x^2)-49 be?
(2x+14 is under a square root)
There's a hole but I do not know how to factor them
Y=_/2x+14)/(x^2)-49 be?
(2x+14 is under a square root)
There's a hole but I do not know how to factor them
Answers
Answered by
Steve
the domain is all reals except where the denominator is zero. So, when is
x^2-49 = 0
?
For the hole, note that 2x+14 = 2(x+7)
x^2-49 = 0
?
For the hole, note that 2x+14 = 2(x+7)
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