Asked by Anonymous
a ball is dropped from the top of a building that is known to be 256 feet high.the formula for finding the height of the ball at any time t is h=256-16t^2,where t is measured in seconds.how many seconds will it take for the ball to hit the ground?
Answers
Answered by
Steve
it hits the ground when the height is zero. So, just solve
256-16t^2 = 0
(16-4t)(16+4t) = 0
...
256-16t^2 = 0
(16-4t)(16+4t) = 0
...
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