Asked by Jessica
Find an A.P. such that the sum of the first three terms is one half the sum of the next four terms, the first term being 12.
Answers
Answered by
Steve
You have:
S3 = 1/2 (S7-S3)
3/2 (24+2d) = 1/2 (7/2 (24+6d) - 3/2 (24+2d))
d = 2
AP = 12,14,16, 18,20,22,24
I'll let you verify the result.
S3 = 1/2 (S7-S3)
3/2 (24+2d) = 1/2 (7/2 (24+6d) - 3/2 (24+2d))
d = 2
AP = 12,14,16, 18,20,22,24
I'll let you verify the result.
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