you want m such that
∫[0,1] (x-x^2)-mx dx = ∫[0,1] mx dx
∫[0,1] x-x^2-2mx dx = 0
(1-2m)/2 x^2 - 1/3 x^3 [0,1] = 0
1 - 2m - 1/3 = 0
m = 1/3
Find the value of m such that y=mx divides the area under the curve y=(1-x)x in [0,1] into two regions of equal area
D: D: D:
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