Asked by chizoba
                Determine a general formula (or formulas) for the solutions to the equation. Then determine the specific solutions (if any) in the interval[0,2π).
2sin^2θ+3sinθ+1=0
            
            
        2sin^2θ+3sinθ+1=0
Answers
                    Answered by
            Steve
            
    another? Why not show how far <i>you</i> get with one of these?
Aside from the trig, it's just algebra I:
(2sinθ+1)(sinθ+1) = 0
...
    
Aside from the trig, it's just algebra I:
(2sinθ+1)(sinθ+1) = 0
...
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