Asked by chizoba
Determine a general formula (or formulas) for the solutions to the equation. Then determine the specific solutions (if any) in the interval[0,2π).
2sin^2θ+3sinθ+1=0
2sin^2θ+3sinθ+1=0
Answers
Steve
another? Why not show how far <i>you</i> get with one of these?
Aside from the trig, it's just algebra I:
(2sinθ+1)(sinθ+1) = 0
...
Aside from the trig, it's just algebra I:
(2sinθ+1)(sinθ+1) = 0
...