Question

the center of gravity of a 100-g stick is located at 50 cm mark and the stick is supported at 60cm. mark, Where must an 80g object be hung in order to have equilibrium?

Answer 1

summing moments about the center:
80x-10*100=0
x=1000/80=100/8 cm from the center on the support side.

Answer 2

thanks

Answer 3

12.5