Asked by Shina omotoye
A ball of mass 0.7Kg is dropped unto a floor from a height of 5m and rebounds to a height of 3m. Find the impulse on the ball when it hits the floor
Answers
Answered by
bobpursley
impulse=changemomentum
= final momentum-initial
now, the ratio of velocities :
from height 5
mg5=1/2 m v^2
or v=sqrt (10g)
and v to get to height 3 m is
v=sqrt(6g)
impulse=changemomentum=m*(sqrt6g+sqrt3g)
= final momentum-initial
now, the ratio of velocities :
from height 5
mg5=1/2 m v^2
or v=sqrt (10g)
and v to get to height 3 m is
v=sqrt(6g)
impulse=changemomentum=m*(sqrt6g+sqrt3g)
Answered by
Mandy
1.5m
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