Asked by Yaga
Simplify and write with positive exponet
(4x^-1)^-1
Work:
(1/4x)^-1
(1/(1/4x))(4x/4x)= 1
(X^3+3x^2+3x+1)^-2/3
Work
1/(X^3+3x^2+3x+1)^2/3
1/(X^2+52/25x^4/3+52/25x+1)
I'm confused on whether these are right or not can someone check my work or explain to me why they're wrong if they are?
(4x^-1)^-1
Work:
(1/4x)^-1
(1/(1/4x))(4x/4x)= 1
(X^3+3x^2+3x+1)^-2/3
Work
1/(X^3+3x^2+3x+1)^2/3
1/(X^2+52/25x^4/3+52/25x+1)
I'm confused on whether these are right or not can someone check my work or explain to me why they're wrong if they are?
Answers
Answered by
Reiny
how about this way:
using (ab)^n = (a^n)(b^n)
(4x^-1)^-1
= (4^-1)(x^-1)^-1
= (1/4)(x^1)
= (1/4)x
or
= x/4
#2
(x^3+3x^2+3x+1)^(-2/3)
= 1/(x^3+3x^2+3x+1)^(2/3)
notice I assumed your exponent was -2/3,
the way you typed it, the exponent would have been -2 , with 3 a divisor
( (x^3+3x^2+3x+1)^-2 )/3
your last line of 1/(X^2+52/25x^4/3+52/25x+1)
makes absolutely no sense to me
using (ab)^n = (a^n)(b^n)
(4x^-1)^-1
= (4^-1)(x^-1)^-1
= (1/4)(x^1)
= (1/4)x
or
= x/4
#2
(x^3+3x^2+3x+1)^(-2/3)
= 1/(x^3+3x^2+3x+1)^(2/3)
notice I assumed your exponent was -2/3,
the way you typed it, the exponent would have been -2 , with 3 a divisor
( (x^3+3x^2+3x+1)^-2 )/3
your last line of 1/(X^2+52/25x^4/3+52/25x+1)
makes absolutely no sense to me