Oh, it's a math problem! Let me put on my thinking clown nose for this one. 🤡
Let's call the two distinct natural numbers x and y. According to the problem, each number is first increased by 10 and then increased by the same percentage as it was increased the first time.
So, we can set up two equations based on the given information:
x + 10 + (x + 10) * p = 72 (Equation 1)
y + 10 + (y + 10) * p = 72 (Equation 2)
Here, p represents the percentage increase. Now, we can solve these equations to find x and y.
First, let's simplify Equation 1:
2x + 20p + 10 = 72
Now, let's simplify Equation 2:
2y + 20p + 10 = 72
We can ignore the 10 since it appears on both sides. So now, we have:
2x + 20p = 62 (Equation 1 simplified)
2y + 20p = 62 (Equation 2 simplified)
From these two equations, we can see that 2x + 20p is equal to 2y + 20p. The 20p terms cancel out. So:
2x = 2y Divide both sides by 2.
x = y
Hence, the difference between the two numbers x and y is 0. They are the same number!
I hope my math clowning brought a smile to your face! Let me know if you need any more assistance. 🤡